# Program to print number of occurrences of each number in the array

#include<iostream.h>

#include<conio.h>

void main()

{

clrscr();

// Coded by : Shahbaz Hashmi

int t,c,p;

int ar[20] = {3,2,1,4,5,6,2,3,5,9,8,6,1,0,7,2,1};

int n = 17; // number of elements

for(int i=0;i<n;i++)

{

t=ar[i];

c=p=0;

for(int j=0;j<n;j++)

{

if(t==ar[j])

{

c++; // for counting occurrence of each number

}

}

for(int k=i+1;k<n;k++)

{

if(t==ar[k])

{

p++; // increments when same number is present ahead in the array

}

}

if(p==0) // checks the number is present ahead or not

{

cout<<t<<” is found “<<c<<” times”<<endl;

}

}

getch();

}

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